Humidity Science & Engineering

Evaporative Cooling Efficiency: How to Calculate It and When It Works

Evaporative cooling efficiency = (dry bulb − supply) ÷ (dry bulb − wet bulb). Typical pad effectiveness, worked examples for dry and humid climates, water use per kWh, and when it fails.

Written byYakeclimate Engineering TeamEngineering TeamReviewed by Jordan Shao, R&D Director
Worked cooling-effectiveness example using 108°F entering dry bulb, 74°F supply and 70°F wet bulb to calculate approximately 89 percent.

Quick answer: Evaporative cooling efficiency (also called saturation or wet-bulb effectiveness) is how close a cooler brings the air to the wet-bulb temperature: efficiency = (outdoor dry bulb − supply air) ÷ (outdoor dry bulb − wet bulb). Good direct pad coolers reach about 70–90 %, indirect coolers about 60–80 %. In dry air the result is a large temperature drop: 40 °C air at 15 % RH can be cooled to about 23 °C. In humid air, the wet-bulb depression is small and the cooler adds humidity without much cooling. In dry climates, direct evaporative coolers can use about a quarter of the energy of central air conditioning (PNNL).

Quick answer
  • Efficiency = (T_dry − T_supply) ÷ (T_dry − T_wet bulb).
  • Direct pads: about 70–90 %; indirect: about 60–80 %.
  • Water use: roughly 1.5 litres evaporated per kWh of cooling.

The formula and a worked example

ε = (T_db − T_supply) ÷ (T_db − T_wb)

  • T_db: dry-bulb temperature of the entering air
  • T_wb: wet-bulb temperature of the entering air
  • T_supply: temperature of the air leaving the cooler

Example: outdoor air at 40 °C and 15 % RH has a wet-bulb temperature of about 20.4 °C. A pad with 85 % effectiveness gives: T_supply = 40 − 0.85 × (40 − 20.4) ≈ 23.3 °C, at about 76 % RH.

What the same cooler does in different climates

Assuming 85 % effectiveness:

Outdoor airWet bulbSupply airSupply RHVerdict
40 °C, 15 % RH (hot desert)20.4 °C23.3 °Cabout 76 %Excellent cooling
35 °C, 20 % RH18.9 °C21.3 °Cabout 80 %Very good
32 °C, 40 % RH21.6 °C23.2 °Cabout 87 %Useful, humid supply
28 °C, 50 % RH20.4 °C21.5 °Cabout 90 %Marginal, very humid supply
32 °C, 70 % RH (humid tropics)27.3 °C28.0 °Cabout 94 %Little cooling, adds humidity

The wet-bulb temperature is the floor for a direct cooler. The wet-bulb depression (dry bulb minus wet bulb) decides how useful it is.

When does evaporative cooling stop working?

It doesn't stop at a fixed temperature: it weakens as the wet-bulb depression shrinks. As a rule of thumb, when outdoor air is above about 60–70 % RH in warm weather (wet-bulb depression below about 5 K), a direct cooler gives little useful cooling and mainly humidifies. In cold weather it isn't needed. Check hours per year with a depression above about 8–10 K for your site.

How to increase evaporative cooling effectiveness

  • Use thicker rigid media pads (about 150–300 mm) with even water distribution.
  • Keep air speed through the pads at the maker's design value; too fast reduces effectiveness and can carry water droplets.
  • Clean and descale pads; control bleed-off and water quality.
  • Seal around pads so air can't bypass them.
  • Pre-cool with an indirect stage (two-stage) in hot, dry climates.
  • Shade the intake; avoid drawing air from hot roofs or exhausts.

Calculating evaporative cooling for a space

Cooling delivered (kW) ≈ airflow (m³/s) × 1.2 kg/m³ × 1.005 kJ/kg·K × (T_room − T_supply)

Example: 5 m³/s of 23 °C supply air holding a space at 29 °C: 5 × 1.2 × 1.005 × 6 ≈ 36 kW of cooling, evaporating about 36 × 1.5 ≈ 54 L of water an hour. A spreadsheet can repeat this for each hour of a weather file to give seasonal cooling and water use.

Typical effectiveness by type

TypeTypical effectivenessAdds moisture to supply air?
Direct, rigid media pads (thick)about 80–90 %Yes
Direct, thin fibre padsabout 60–80 %Yes
Indirect (heat exchanger)about 60–80 % of wet-bulb depressionNo
Two-stage (indirect then direct)Can supply air below the outdoor wet bulbLess than direct alone

Effectiveness falls with dirty or scaled pads, poor water distribution and air bypass. See indirect evaporative cooling explained.

Energy and water

  • Energy: only fans and a water pump. PNNL's Building America Solution Center notes that in dry climates direct evaporative coolers can use about one quarter of the energy of central air conditioners (PNNL BASC).
  • Water: evaporating 1 kg of water absorbs about 0.68 kWh, so about 1.5 litres evaporate for each kWh of cooling, plus bleed-off water to control scale. A cooler delivering 20 kW of cooling evaporates about 30 L/h.

The US GSA has evaluated indirect evaporative coolers for federal buildings (GSA).

Evaporative cooling and humidity control

Direct evaporative cooling is the opposite of dehumidification: it cools by adding water to the air. That matters when:

  • greenhouses use pad and fan cooling: humidity rises through the house and becomes a problem when the pads stop at night; see greenhouse humidity by climate and the NSW Department of Primary Industries guide to evaporative cooling in greenhouses (NSW DPI);
  • warehouses and factories hold moisture-sensitive goods;
  • humid weather arrives: the cooler gives little cooling and humid supply air.

Do not run a dehumidifier against an open direct evaporative cooler; they cancel each other. Where both cooling and dry air are needed in humid climates, use mechanical cooling with dehumidification, or indirect evaporative cooling plus a dehumidifier for the moisture load. Our industrial dehumidifiers cover the moisture side.

How to estimate if it will work at your site

  1. Find the design dry-bulb and coincident wet-bulb temperatures for your location (local climate data or the ASHRAE design conditions).
  2. Calculate supply temperature with a realistic effectiveness (75–85 %).
  3. Check supply RH against what the space and its contents can accept.
  4. Check the hours per year with a useful wet-bulb depression (often above about 8–10 K).
  5. Include water supply, water treatment and bleed-off.

FAQ

Frequently asked questions

How do you calculate evaporative cooling efficiency?

Efficiency = (entering dry bulb − leaving air temperature) ÷ (entering dry bulb − entering wet bulb).

What is a good evaporative cooler efficiency?

About 80–90 % for good rigid media pads; 60–80 % for indirect coolers.

Does evaporative cooling work in humid climates?

Poorly. With a small wet-bulb depression, it cools little and adds humidity.

What temperature does evaporative cooling stop working?

There is no single temperature; it becomes ineffective when the air is humid (small gap between dry-bulb and wet-bulb temperatures), typically above about 60–70 % RH in warm weather.

How can the effectiveness of evaporative cooling be increased?

Thicker, clean pads with even wetting, correct air speed, no bypass, good water treatment, and an indirect pre-cooling stage.

How much water does an evaporative cooler use?

About 1.5 litres evaporated per kWh of cooling, plus bleed-off.

Sources

  • PNNL Building America Solution Center, Evaporative cooling systems.
  • US GSA, Indirect evaporative cooler technology evaluation.
  • NSW Department of Primary Industries, Evaporative cooling in greenhouses.
  • REHVA, Evaporative cooling guidebook.
  • ASHRAE Handbook—Fundamentals, Psychrometrics.

About the author

Yakeclimate Engineering Team

Engineering Team

Yakeclimate technical articles are prepared by the engineering team using inputs from product development, application review, manufacturing, testing, and project support.

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Reviewed by Jordan Shao, R&D Director

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